# add array elements total in C++

In this program, we will input some numbers from the user and print their total.

In the program, we have declared three variables.

`int arr,num,sum=0;`

In which the variable sum has been initialized.

Here, we have given 10 the size of the array arr. Which means that we can only store maximum 10 elements in an array-variable arr[] at a time.

aLet’s start.

```#include<iostream.h>
#include<conio.h>

void main()
{
int arr,num,sum=0;
clrscr();

cout<<"Enter The array size \n";
cin>>num;

cout<<"Enter "<<num<<" Element: ";

for(int i=0;i<num;i++)
cin>>a[i]; // store values in variable a[]

for(int j=0; j<n;j++)
{
cout<<a[j]<<" ";     // print array element
sum=sum+a[j];      // sum of array element
}

//Print sum of array element
cout<<"\nTotal of These Element are: "<<sum;

getch();
}```
```OUTPUT:-
Enter The array size: 6
Enter 6 Element:
4 8 9 1 4 2

Your element is: 4 8 9 1 4 2

Total of These Element are : 28```

explanation

Suppose the user has given an array size 6,

`num = 6`

And the 6 elements were stored in this way,

```arr = 4
arr = 8
arr = 9
arr = 1
arr = 4
arr = 2```

now loop will start from here,

1st j = 0 n = 6

```for(int j = 0; 0 < 6; 0++)
{
cout<<4<<" ";
sum=0+4;
}```

2nd j = 1, num = 6, sum = 4

```for(int j=1; 1 < 6; 1++)
{
cout<<8<<" ";
sum=4+8;
}```

3rd  j = 2, num = 6, sum=12

```for(int j=2; 2 < 6; 2++)
{
cout<<9<<" ";
sum=12+9;
}```

4th  j = 3, num = 6, sum = 21

```for(int j=3; 3 < 6; 3++)
{
cout<<1<<" ";
sum=21+1;
}```

5th  j = 4 num = 6, sum = 22

```for(int j=4; 4 < 6; 4++)
{
cout<<4<<" ";
sum=22+4;
}```

6th  j = 5, num = 6, sum = 26

```for(int j=5; 5 < 6; 5++)
{
cout<<2<<" ";
sum=26+2;
}```

7th  j = 6, num = 6, sum = 28

```for(int j=6; 6 < 6; 5++)
{
skip
}```

In 7th execution condition becoming false 6<6 so here loop will be terminate and outside the loop will next statement execute,

outside the loop variable sum value will be print which is now 28.

so thus program will execute successfully.