# find out in given number, even or odd in C++

In this program, we will find out whether the input entered by the user is even or odd,

We know that those numbers which are completely divided by 2 are called even numbers meaning the remainder is 0 and those that do not divide completely are called odd numbers.

So the condition here will be something like this,

for even number

`number%2 == 0`

for odd number

`number%2 != 0`

We will use either of these two conditions in the program here.

```#include<iostream.h>
#include<conio.h>
void main()
{
clrscr();
int num;  //variable declaration

cout<<"Enter a number:";
cin>>num;

cout<<endl;

if(num%2==0)      // expression
cout<<num<<" is even number"; // body of if

else

cout<<num<<" is odd number";// body of else

getch();
}```
```OUTPUT:-

1st Execution
Enter a number: 4
4 is even number

2nd Execution
Enter a number: 3
3 is odd number```

explanation:

In first execution user input is 4 which will store in variable number

`number = 4`

After this, the condition will be checked in the if statement, such as

`4%2==0`

Because remainder is 0. means the condition is becoming true, the body of if will be execute

In 2nd execution user input is 3

`number =3`

And as such, the condition will be checked after this

`3%2==1.5`

And because remainder is not 0, means condition is becoming false, the body of if will be skipped and the body of else will be executed.

Thus program successfully executed.

we can also use both condition such as,

```if(num%2!=0)
cout<<"Given number is odd";

else if(num%2==0)
cout<<"Given number is even";```